Question 1204058
we need two points from give graph that lie on a line

({{{ -10}}},{{{ 0}}}) and ({{{ 0}}},{{{ 4}}})


equation of a line is:

{{{y=mx+b  }}}

where {{{m}}} is a slope, and {{{b }}}is y-intercept


since  ({{{0}}},{{{4}}}) is y-intercept => {{{b=4}}}


now we need to find a slope using two points above

{{{m=(4-0)/(0-(-10))=4/10=2/5}}})

your equation of a line is:

{{{y=(2/5)x+4}}}


{{{ drawing( 600, 600, -15, 15, -10, 15,
circle(0,4,.12), circle(-10,0,.12),
locate(0,4,p(0,4)),locate(-10,0.8,p(-10,0)),

graph( 600, 600, -15, 15, -10, 15,(2/5)x+4)) }}}