Question 1204054
{{{log(0.5)/log(25)}}}.....assuming the base is {{{10}}}


={{{log(5/10)/log(5^2)}}} 


={{{(log(5)-log(10))/2log(5)}}} 


={{{(log(5)-log(2*5))/2log(5)}}} 


={{{(log(5)-(log(2)+log(5)))/2log(5)}}} 


={{{(log(5)-log(2)-log(5))/2log(5)}}} 


={{{-log(2)/2log(5)}}} => exact solution


={{{-0.2153382790367}}}=> approximate solution