Question 1203987
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A = 1st selection is sugar cookie
B = 2nd selection is oatmeal cookie


P(A) = (6 sugar)/(6+8+6+7 total)
P(A) = 6/27


P(B given A) = (7 oatmeal)/(27-1 remaining)
P(B given A) = (7 oatmeal)/(26 remaining)
P(B given A) = 7/26


P(A and B) = P(A)*P(B given A)
P(A and B) = (6/27)*(7/26)
P(A and B) = (6*7)/(27*26)
P(A and B) = (2*3*7)/(3*9*2*13)
P(A and B) = 7/(9*13)
P(A and B) = 7/117


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Answer: <font color=red size=4>7/117</font>
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