Question 1203986




Let {{{ t }}}= time traveled at {{{ 53mph}}}
then
{{{ (3.5-t)}}} = time traveled at {{{ 59mph}}}

Total time is given as {{{ 3.5h}}}, therefore


Write distance equation; 

{{{ d = s*t}}}
{{{ 53t + 59(3.5-t) =200.5}}}
{{{ 206.5 - 6 t = 200.5}}}
{{{ 206.5 -200.5 = 6 t }}}
{{{ 6 = 6 t}}} 
{{{ t=1}}}

so,

 {{{ t=1}}}=>Charles traveled {{{ 1h }}}at {{{ 53mph}}}
{{{ (3.5-t)=3.5-1=2.5}}}=>Charles traveled {{{ 2.5h}}} at {{{ 59mph}}}