Question 1203974


 {{{ h(x)=x^2+3x+2}}}  on the interval {{{ -3 <=x <=-1}}} 

the average rate of change of the function

average rate={{{ (h(a)-h(b))/(b-a)}}} 

in your case {{{ a=-3 }}} and{{{  b=-1}}} 

{{{ h(-3)=(-3)^2+3(-3)+2=9-9+2=2}}} 
{{{ h(-1)=(-1)^2+3(-1)+2=1-3+2=0}}} 

average rate={{{ (2-0)/(0-2)=2/-2=-1}}}