Question 1203967
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The two responses you have received showing a solution using substitution are valid.<br>
I would change the form of the second equation, after which a solution by either substitution or elimination is obvious.<br>
(1) y = 2x-3
(2) -6x+3y = -9 --> 3y = 6x-9 --> y = 2x-3<br>
We see the two equations are equivalent, so the solution is all the sets of ordered pairs that satisfy the equation.<br>
Finishing the problem formally using substitution, we would have<br>
2x-3 = 2x-3
2x-2x = 3-3
0 = 0<br>
Which is always true...<br>
or by elimination<br>
y = 2x-3
y = 2x-3
0 = 0 (by subtraction)<br>
which again is always true.<br>