Question 1203958
Application of linear equation



Points (x,y) for time in years x and amount of farmland y
{{{y=mx+b}}}, may be the form of equation of choice.


THE SLOPE m, IS GIVEN AS  3.27 million acres per year, and is negative.
You can let year 1987 be assigned time 0 and you are given a point  (10,931.8).


That should be enough for you to continue the rest of the way.


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Notice you need to read the description very carefully.  
Time 0 can be year 1987;
and time 10 would be year 1997.
The amount of farmland was 931.8 million acres IN YEAR 1997, which is at x=10.


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One might be more confortable using point-slope equation form.

{{{y-931.8=-3.27(x-10)}}}
and put this into slope-intercept form.