Question 1203912
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Two machines turn out all the products in a factory, with the first machine producing 57% of the product 
and the second machine producing the rest. 
The first machine produces defective products 6% of the time and the second machine 2% of the time. 
What is the probability that a part made in this factory is not defective? 
(Enter answer as a decimal with at least 4 correct decimal places)
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If to think one - two minutes, the solution, the formula and answer can be written in one line

    P = 0.57*(1-0.06) + (1-0.57)*(1-0.02) = 0.9572.    <U>ANSWER</U>
</pre>

Solved.


The formula is SELF-EXPLANATORY.


Look in it attentively, and it will tell you a whole story.