Question 1203891
<br>
The 450 adult tickets, each costing $3 more than a student ticket, bring in an "additional" 450($3) = $1350.<br>
So the total of $9400 can be thought of as 450+700 = 1150 tickets costing the same amount, plus the additional $1350.  That means the 1150 tickets that each cost the same sell for a total of $9400-$1350 = $8050.  The cost for each of them is then $8050/1150 = $7.<br>
ANSWER: The student tickets should cost $7 each, the adult tickets $7+$3 = $10 each.<br>
Solving the problem in exactly the same way using formal algebra looks like this:<br>
x = cost of a student ticket
x+3 = cost of an adult ticket<br>
700(x)+450(x+3) = 9400
700x+450x+1350 = 9400
1150x = 8050
x = 8050/1150 = 7<br>
Student ticket cost: x = $7
Adult ticket cost: x+3 = $10<br>