Question 1203898


 let two-bedroom units be {{{x}}} and three-bedroom units {{{y}}}

if a real estate developer recently built 210 condominiums, we have

{{{x+y=210}}}...solve for {{{y}}}

{{{y=210-x}}}...eq.1

two-bedroom units have total of {{{2x}}} bedrooms and three-bedroom units {{{3y}}} bedrooms

If the total number of bedrooms in the entire complex is {{{537}}}, 

{{{2x+3y=537}}}....eq.2, substitute {{{y}}}

{{{2x+3(210-x)=537}}}

{{{2x+630-3x=537}}}

{{{630-x=537}}}

{{{630-537=x}}}

{{{x=93}}}

go to

{{{y=210-x}}}...eq.1, substitute {{{x}}}

{{{y=210-93}}}

{{{y=117}}}


there are {{{93}}} two-bedroom units 

 there are {{{117}}} three-bedroom units