Question 1203851
.
A die is rolled. Find the probability of the given event. Round all answers to 4 decimals.
(a) The number showing is a 6;
The probability is :

(b) The number showing is an even number;
The probability is :

(c) The number showing is greater than 2;
The probability is :
~~~~~~~~~~~~~~~~~~~~~~~~~


<pre>
(a)  There are 6 possible outcomes 1, 2, 3, 4, 5, 6.

     Of them, only one outcome is desirable: 6.

     The probability to get this outcome is  {{{1/6}}}.



(b)  There are 6 possible outcomes 1, 2, 3, 4, 5, 6.

     Of them, exactly THREE outcomes are desirable: 2, 4, 6.

     The probability to get a desirable outcome is  {{{3/6}}} = {{{1/2}}}.



(c)  There are 6 possible outcomes 1, 2, 3, 4, 5, 6.

     Of them, exactly FOUR outcomes are desirable: 3, 4, 5, 6.

     The probability to get a desirable outcome is  {{{4/6}}} = {{{2/3}}}.
</pre>

Solved.


The instruction to round the answers to &nbsp;4 &nbsp;decimals looks like &nbsp;IRRELEVANT.


When the answers are so beautiful fractions, &nbsp;reflecting the meaning of the solution,
the request to present them as decimals does not seem very smart.


I would say, &nbsp;in  opposite, &nbsp;it shows that the problem's composer does not think on what he &nbsp;(or she) &nbsp;writes.



/////////////////////



<H3>The lesson to learn from this my post</H3>

The lesson to learn and the general instruction on how to solve similar problems is THIS:


    &nbsp;&nbsp;&nbsp;&nbsp;- determine the total number of all possible different outcomes;


    &nbsp;&nbsp;&nbsp;&nbsp;- determine the number of all possible desired, &nbsp;or favorable, &nbsp;outcomes.


    &nbsp;&nbsp;&nbsp;&nbsp;- Then the probability &nbsp;(or the answer to the problem's question) &nbsp;is  &nbsp;&nbsp;P = {{{favorable/total}}}.