Question 1203745
<pre>
A man has $250,000 invested in three properties. One earns 12%, one 10% and one 8%. His annual income from the properties is $23,900 and the amount invested at 8% is twice that invested at 12%.
(a) How much is invested in each property?
12%property			$ 
10%property			$ 
8%property			$ 


(b) What is the annual income from each property?
12%property			$ 
10%property			$ 
8%property			$ 

Let amount invested in the property earning 12%, be T
Then amount invested in the property earning 8% = 2T
So, amount invested in the property earning 10% = 250,000 - (T + 2T) = 250,000 - 3T

Income from property earning 12%: .12T
Income from property earning 8%: .08(2T) = .16T
Income from property earning 10%: .1(250,000 - 3T) = 25,000 - .3T

Since total income from the 3 investments is $23,900, we get: .12T + .16T + 25,000 - .3T = 23,900
                                                                       .12T + .16T - .3T = 23,900 - 25.000
                                                                                  - .02T = - 1,100 
    <font color = red><font size = 3><b>Amount invested in property earning 12%</font></font></b>, or {{{highlight_green(matrix(1,9, T, "=", "- 1,100"/(- .02), "=", "- 110,000"/(- 2), "=", "110,000"/2, "=", highlight("$55,000")))}}}

                         <font color = red><font size = 4><b>Amount invested in property earning 8%:</font></font></b> 2T = 2(55,000) = <font color = red><font size = 4><b>$110,000</font></font></b>

  <font color = red><font size = 2><b>Amount invested in property earning 10%:</font></font></b> 250,000 - (55,000 + 110,000) = 250,000 - 165,000 = <font color = red><font size = 4><b>$85,000</font></font></b>

Income from property earning 12%, property earning 8%, and property earning 10% are: .12T, .16T, and 25,000 - .3T,
respectively. Use those facts, along with T being $55,000, to find the income from each of the 3 properties.</pre>