Question 1203833
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Given equations
x/y = 4/5
y/z = 2/5
z/w = 6/11


Multiply equations (1) and (2).
We multiply left hand sides (LHS) separately. 
Do the same for the right hand sides (RHS)


LHS: (x/y) * (y/z) becomes x/z
RHS: (4/5)*(2/5) becomes 8/25


We conclude that x/z = 8/25
The key here is that z is the denominator.


Apply the reciprocal to both sides of equation (3) to get w/z = 11/6
We have z in the denominator as well.


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So we have:
x/z = 8/25
y/z = 2/5
w/z = 11/6
All three equations shown above have z in the denominator.


Add them up.
(x/z) + (y/z) + (w/z) = (8/25)+(2/5) + (11/6)
(x + y + w)/z = (8/25)+(10/25) + (11/6)
(x + y + w)/z = (18/25) + (11/6)
(x + y + w)/z = (18/25)*(6/6) + (11/6)*(25/25)
(x + y + w)/z = (108/150) + (275/150)
(x + y + w)/z = (108+275)/150
(x + y + w)/z = <font color=red size=4>383/150</font>
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