Question 1203830
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In your post, you repeated your question twice.



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<U>comment from student</U> : &nbsp;&nbsp;Oh my goodness I am so sorry it was supposed to be what is the 


&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;"what is the probability she doesn't roll a 6 until her THIRD attempt?"



<U>My response</U> : &nbsp;&nbsp;It is just much better.


<pre>
(a)  Question (a) asks to find the probability that first roll is not 6.

         P = {{{5/6}}}.



(b)  Question (b) asks to find the probability that NEITHER first NOR second roll is 6.


         P = {{{(5/6)*(5/6)}}} = {{{25/36}}}.    <U>ANSWER</U>
</pre>

Solved.