Question 1203824


decide what values of the variable cannot possibly be solutions for the equation

{{{1/(x-3 )+ 1/(x+2 )= 1/(x^2-x-6)}}}

{{{((x+2 )+ (x-3 ))/((x+2 )(x-3 ))= 1/((x + 2) (x - 3))}}}

since denominator cannot be equal to zero, the values of the variable cannot possibly be solutions are:

{{{(x + 2) =0}}}=> {{{x=-2}}}
or
{{{(x - 3)=0}}}=> {{{x=3}}}