Question 1203825
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A bullet of mass 180g is fired horizontally into a fixed wooden block with a speed of 24m/s. 
If the bullet is brought to rest in 0.4 seconds by a constant resistance, 
calculate the distance moved by the bullet in the wood.
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<pre>
We have uniformly decelerated movement with the initial speed of 24 m/s
and the final speed of 0 m/s after 0.4 seconds


So, we can calculate the deceleration value "a": it is  a = {{{24/0.4}}} = 60 m/s^2.


Now we can calculate the distance to stop

    {{{D[stop]}}} = {{{(at^2)/2}}} = {{{(60*0.4^2)/2}}} = 4.8 meters.    <U>ANSWER</U>
</pre>

Solved, with full explanations.


The mass of the bullet of 180 g, given in the post, is irrelevant to the problem.