Question 1203670
<pre>
 line’s equation is given in point-slope form: y=(-2/9)(x+9)+1

This line’s slope is -2/9

What is a point on this line that is apparent from the given equation?

*I've tried (0,-1), (-9/2,0), (-2,-5/9) but all these answers are wrong


Point-slope form of a linear equation: {{{matrix(1,3, y - y[1], "=", m(x - x[1]))}}}   

For y = {{{(-2/9)}}}(x + 9) + 1, we need to subtract 1 from both sides of the equation. 
When done, y = {{{(-2/9)}}}(x + 9) + 1 becomes: {{{matrix(1,3, y - 1, "=", (- 2/9)(x + 9))}}}  
                            Compared to: {{{matrix(1,3, y - y[1], "=", m(x - x[1]))}}}, we see that: 
                                          {{{matrix(3,3, - y[1], "=", - 1, y[1], "=", (- 1)/(- 1), y[1], "=", 1)}}}, and also: {{{matrix(3,3, - x[1], "=", 9, x[1], "=", 9/(- 1), x[1], "=", - 9)}}}
Therefore, (x<sub>1</sub>, y<sub>1</sub>) = <font color = red><font size = 4?<b>(- 9, 1).</font></font></b> This is your point on the line, from the given equation.</pre>