Question 1203782

𝐸 is the midpoint of 𝐷F. 𝐷𝐸 = 4π‘₯ + 3
and 𝐸𝐹 = 8π‘₯ βˆ’ 9. Find 𝐷𝐸, 𝐸𝐹, and 𝐷

Since e is the midpoint of DF DE = EF

Therefore 4x+3 = 8x-9

subtract 8x from both sides of equation

4x+3-8x = -9

substract 3 from both sides

4x -8x = -9-3

-4x = -12

x = -12/-4=3

DE = 4x+3 
plug x

DE = 4*3+3

DE = 15

Therefore EF = 15