Question 1203699
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The distance is 1080m.<br>
The time required for them to pass each other is 6 minutes, or 360 seconds.<br>
So their combined rate is 1080/360 = 3m/s.<br>
Formal algebra should not be needed to see that, if their combined rate is 3m/s and the jogger's rate is 1m/s faster than the walker's, then the walker's rate is 1m/s and the jogger's rate is 2m/s.<br>
Then with the jogger's rate equal to twice the walker's rate, it should be easy to determine that the jogger covers 2/3 of the 1080m, or 720m.<br>
ANSWER: they meet 720m from Oakville Mall.<br>