Question 1203681


The point {{{P}}} is on the {{{unit}}} circle. 

Find P({{{x}}}, {{{y}}}) from the given information.


The {{{x}}}-coordinate of {{{P }}}is {{{7/25}}}, and the {{{y}}}-coordinate is {{{negative}}}

so far P({{{7/25}}}, {{{-y}}})


the unit circle=> {{{r=1}}} and center is at {{{origin}}}

so, the formula for unit circle is

{{{x^2 + y^2=1}}}....substitute{{{ x}}}

{{{(7/25)^2 + y^2=1}}}

{{{y^2=1-(7/25)^2 }}}

{{{y^2=1-49/625}}} 

{{{y^2=576/625}}}

{{{y=sqrt(576/625)}}}

solutions:

{{{y=24/25}}}

or

{{{y=-24/25}}}


since the {{{y}}}-coordinate is negative, point is at

{{{P(7/25,-24/25)}}}