<PRE><B>Question 1203653</B>
&lt;br&gt;
You have received two responses showing a standard algebraic method for solving the problem.&lt;br&gt;
Here is a solution using a very different method.&lt;br&gt;
The two speeds are 25mph and 30mph, a ratio of 5:6.&lt;br&gt;
Since the distances are the same, the ratio of times at the two speeds is 6:5.&lt;br&gt;
The time at the higher speed is 1/2 hour less than the time at the lower speed.&lt;br&gt;
x = hours at lower speed
x-1/2 = hours at higher speed&lt;br&gt;
The ratio is 6:5&lt;br&gt;
{{{x/(x-(1/2))=6/5}}}
{{{6(x-(1/2))=5x}}}
{{{6x-3=5x}}}
{{{x=3}}}&lt;br&gt;
The time spent at the lower speed was 3 hours.  Since the lower speed was 25mph, the distance was 3*25 = 75 miles.&lt;br&gt;
ANSWER: 75 miles&lt;br&gt;
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