Question 1203630
slope intercept form of the equation of a straight lin is y = mx + b.
m is the slope
b is the y-intercept.


your two points are (2,5) and (-3,-1)
let (2,5) be (x1,y1)
let (-3,-1) be (x2,y2)


slope is equal to (y2-y1)/(x2-x1) = (-1-5)/(-3-2) = -6/-5 =  6/5.
straight line equation becomes y = 6/5 * x + b


to find the value of b, replace x and y with the value from one of the points and solve.
i chose (2,5)
y = 6/5 * x + b becomes 5 = 6/5 * 2 + b which becomes 5 = 2.4 + b.
solve for b to get b = 5 - 2.4 = 2.6.
the value of b is 2.6 and the equation becomes:
y = 6/5 * x + 2.6
since 6/5 = 1.2, the equation can also be shown as y = 1.2 * x + 2.6


replacing x with 2 gets y = 5
replacing x with -3 gets y = -1
this confirms the points are on the line.


a graph of the equation shows the same, as shown below.


<img src = "http://theo.x10hosting.com/2023/091301.jpg">