Question 1203539
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One log rule is ln(A)-ln(B) = ln(A/B)


But there isn't a log rule for ln(A-B)


I think there might be a typo in your textbook.


I suppose this could be one pathway to take, but it's a bit convoluted and messy.
x = ln(A)
y = ln(B)
A = e^x
B = e^y
A-B = e^x - e^y
A-B = e^x(1 - e^(y-x))
Ln[A-B] = Ln[ e^x(1 - e^(y-x)) ]
Ln[A-B] = Ln[e^x] + Ln[1 - e^(y-x) ]
Ln[A-B] = 1 + Ln[1 - e^(y-x)]
But we run into the same problem of having a log of the form Ln(something - somethingElse)
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