Question 1203538
<font color=black size=3>
x = starting number of jellybeans on Monday
<table border = "1" cellpadding = "5"><tr><td></td><td>Count at end of day</td></tr><tr><td>Monday</td><td>x</td></tr><tr><td>Tuesday</td><td>(2/3)x+60</td></tr><tr><td>Wednesday</td><td>( (2/3)x+60 ) - 220 + 60</td></tr><tr><td>Thursday</td><td>(5/9)*( (2/3)x+60 )</td></tr></table>
Equate the last two expressions.
Solve for x.
( (2/3)x+60 ) - 220 + 60 = (5/9)*( (2/3)x+60 )
(2/3)x - 100 = (5/9)*(2/3)x+(5/9)*(60)
(2/3)x - 100 = (10/27)x+(100/3)
27*( (2/3)x - 100 ) = 27*( (10/27)x+(100/3) )
18x - 2700 = 10x+900
18x-10x = 900+2700
8x = 3600
x = 3600/8
x = 450 is the starting amount on Monday
Since the jelly beans aren't eaten on Monday, it's the ending amount on Monday.


Let's find the amount at the end of Wednesday.
( (2/3)x+60 ) - 220 + 60 
(2/3)x - 100
(2/3)*450 - 100
300 - 100
200



Answers:
Amount at end of Wednesday = 200
Amount at end of Monday = 450
</font>