Question 1203532
i think this is goiing to be a binomial distriution type problem.
there are 16 containers in the box, 6 of which are defective.
probability of any one container being defective is 6/16.
you randomly choose 5 out of the 16.
the binomial distibution formula is p(x) = p^x * (1-p)^(n-x) * c(n,x)
the probability that exactly 2 out of the 5 are defective would be:
p(2) = (6/16)^2 * (1 - 6/16)^(5-2) * c(5,2) = .3433227539.
the total probability should be 1, as shown in the following excel file display.
<img src = "http://theo.x10hosting.com/2023/090801.jpg">