Question 1203469
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The pole is 7 meters tall. Half of this is 3.5 meters which is the shadow length.
x = unknown angle of elevation


Draw a right triangle with:
vertical leg = 7 = opposite angle x
horizontal leg = 3.5 = adjacent to angle x
{{{
drawing(400,400,-5,5,-5,5,
line(2,-2,-2,2),
line(-2,2,-2,-2),
line(-2,-2,2,-2),

line(-2,-2+0.3,-2+0.3,-2+0.3),
line(-2+0.3,-2+0.3,-2+0.3,-2),

locate(-0.5,-2.1,3.5), 
locate(-0.5,-2.1-0.5,"adjacent"), 
locate(-2.5, 0, 7), 
locate(-3.7, 0.5, "opposite"), 
locate(2-1.3,-2+0.8, x^o),

locate(-4.5,-4,matrix(1,2,"Diagram","not")), 
locate(-4.5,-4.5,matrix(1,2,"to","scale")) 
)
}}}


tan(angle) = opposite/adjacent
tan(x) = 7/3.5
tan(x) = 2
x = arctan(2)
x = 63.434948822922
x = <font color=red>63 degrees</font>
Arctan is the same as inverse tangent. Make sure that your calculator is in degree mode.



Answer: <font color=red>63 degrees</font> (approximate)
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