Question 1203424
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Use the pythagorean theorem to find that hypotenuse BC = 6*sqrt(2)
Or you can use the 45-45-90 triangle template.


Let D = midpoint of B and C


It turns out that any right triangle will have its circumcenter at the midpoint of the hypotenuse.


This means we can draw a circle centered at D, and radius 3*sqrt(2). 
This circumcircle passes through A, B, and C.


The distance from A to D is 3*sqrt(2), aka the radius of this new circle.
Therefore, segment AD = 3*sqrt(2)


Use this info to determine the radius of each small arc. 


To get the distance along a circle's edge, you'll need this formula
arc length = (angle in radians)*r


45 degrees = pi/4 radians
90 degrees = pi/2 radians


I'll let the student finish up from here.
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