Question 1203396
<pre>
{{{h}}}{{{""=""}}}{{{H +v(v^""/g^"")-(1^""/2^"")g(v^""/g^"")^2}}}   

{{{h}}}{{{""=""}}}{{{H +v^2/g^""-(1^""/2^"")g(v^2/g^2)}}}

{{{h}}}{{{""=""}}}{{{H +v^2/g^""-(1^""/2^"")cross(g)(v^2/g^cross(2))}}}

{{{h}}}{{{""=""}}}{{{H +v^2/g^""-(1^""/2^"")(v^2/g^"")}}}

{{{h}}}{{{""=""}}}{{{H +v^2/g^""-v^2/(2g^"")}}}

Multiply through by 2g

{{{2gh}}}{{{""=""}}}{{{2gH +2v^2-v^2}}}

{{{2gh}}}{{{""=""}}}{{{2gH +v^2}}}

{{{2gh-2gH}}}{{{""=""}}}{{{v^2}}}

{{{2g(h-H)}}}{{{""=""}}}{{{v^2}}}

{{{"" +- sqrt(2g(h-H)))}}}{{{""=""}}}{{{v}}} if {{{h>=H}}}

The other tutor left off the fact that the answer is only valid if {{{h>=H}}}

If you inadvertently typed a capital H for a little h,
then the answer is 0.

Edwin</pre>