Question 1203379
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(a) Leo and issac had 95 balls together. 
(b) Leo gave away 3 more than issac. 
(c) Issac was left with 5 fewer than the balls he gave away. 
(d) Leo had 2 more balls left than issac. 
How many did Leo give away.
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<pre>
x = Leo had initially
y = Issac had initially
z = Leo gave away

From (a), we have this equation   x + y = 95.             (1)

From (b), Issac gave away (z-3).

From (c), we have this equation   y - (z-3) = ((z-3)-5),  or   y - 2z = -11   (2)

From (d), we have this equation   x - z = y - (z-3) + 2,  or   x -  y =   5   (3)



Thus, we have this system of equations

    x +  y      =  95    (1)

         y - 2z = -11    (2)

    x -  y      =   5    (3)


Add equations (1) and (3).  Get  2x = 100,  x = 100/2 = 50.    (Leo had initially)


Then from (1),  y = 95 - x = 95 - 50 = 45.                     (Issac had initially)


Then from (2),  2z = y + 11 = 45 + 11 = 56,  z = 56/2 = 28.    (Leo gave away)


<U>ANSWER</U>.  Leo gave away 28 balls.


<U>CHECK</U>.  Issac gave away 28-3 = 25.

        Issac was left with 45 - 25 = 20.

        Leo was left with 50 - 28 = 22.

        Leo left - Issac left = 22 - 20 = 2   (correct).
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Solved.