Question 1203312
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According to Wolfram MathWorld,
<a href="https://mathworld.wolfram.com/Zone.html">https://mathworld.wolfram.com/Zone.html</a>
A zone is like a partial bit of the sphere's surface. We can think of it like a small piece of an orange peel. That link marks the zone in blue.


Here's another article talking about the topic
<a href="https://en.wikipedia.org/wiki/Spherical_segment">https://en.wikipedia.org/wiki/Spherical_segment</a>
A spherical segment is a wedge-shaped 3D solid that forms after making those two parallel cuts of the sphere. The zone is then the outer surface area. 


On either page is the formula {{{S = 2*pi*R*h}}}
pi = 3.14 approximately (use more decimal digits of pi to get better accuracy)
R = radius of the sphere
h = height aka altitude
S = surface area of the zone


In this case we are given
S = 50.265
h = 2


We'll use those items to find the radius R.
{{{S = 2*pi*R*h}}}


{{{50.265 = 2*3.14*R*2}}}


{{{50.265 = 12.56R}}}


{{{R = (50.265)/(12.56)}}}


{{{R = 4.00199045}}} approximately


Now we can determine the surface area of the sphere
{{{SA = 4*pi*R^2}}}


{{{SA = 4*3.14*4.00199045^2}}}


{{{SA = 201.16005}}} 


<font color=red>The surface area of the entire sphere is approximately 201.16005 square cm.</font>


In a real life example, this would be the entire orange peel (as opposed to the small piece of it mentioned earlier).
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