<PRE><B>Question 1203271</B>
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The conditions tell us the parabola opens downward, with axis of symmetry at x=-1.&lt;br&gt;
We are given that f(t) is greater than f(0).&lt;br&gt;
By symmetry, f(-2) = f(0) (-2 and 0 are the same distance from the axis of symmetry).&lt;br&gt;
So f(-2) = f(0), f(t) is greater than f(0), the parabola opens downward, and the axis of symmetry is at x=-1.  That means that t must be between -2 and 0, which is condition I.&lt;br&gt;
So I is true.&lt;br&gt;
Given that f(t) is greater than f(0) and f(-2) = f(0), f(t) is also greater than f(-2).  So condition II is false.&lt;br&gt;
We are given that f(t) is greater than f(0). x=1 is farther to the right of the axis of symmetry than x=0; since the parabola opens downward, f(t) is greater than f(1).&lt;br&gt;
So III is true.&lt;br&gt;
I and III are true and II is false, so the answer is (C) I and III only.&lt;br&gt;
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