Question 1203266
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<pre>

The binomial distribution with the number of trials n= 10;
probability of "success" in each individual trial p= {{{4/20}}} = {{{1/5}}} = 0.2;
and the number of "successful" trials k= 5.


Use the standard formula for the probability


   P = {{{C[10]^5*0.2^5*(1-0.2)^(10-5)}}} = {{{((10*9*8*7*6)/(1*2*3*4*5))*0.2^5*0.8^5}}} = 0.02642.   (rounded).    <U>ANSWER</U>
</pre>

Solved.


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To see many other similar solved problems of this type, &nbsp;look into the lessons

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/Probability-and-statistics/Solving-problems-on-Binomial-distribution-manually.lesson>Simple and simplest probability problems on Binomial distribution</A> 

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/Probability-and-statistics/Typical-binomial-distribution-probability-problems.lesson>Typical binomial distribution probability problems</A> 

in this site.


Learn the subject from there.