Question 115281
Start with the given system

{{{2y-4x=-3}}}
{{{y=2x+4}}}




{{{2(2x+4)-4x=-3}}}  Plug in {{{y=2x+4}}} into the first equation. In other words, replace each {{{y}}} with {{{2x+4}}}. Notice we've eliminated the {{{y}}} variables. So we now have a simple equation with one unknown.



{{{4x+8-4x=-3}}} Distribute



{{{8=-3}}} Combine like terms on the left side



{{{0=-3-8}}}Subtract 8 from both sides



{{{0=-11}}} Combine like terms on the right side



{{{0=-11}}} Simplify


Since this equation is <font size=4><b>never</b></font> true for any x value, this means there are no solutions.



So the system is inconsistent