Question 1203234

given:

{{{x}}}=>smaller number

{{{y}}}=>larger number


{{{ x+y=200 }}}

 {{{y=200-x }}}.....eq.1

{{{ y=3x-8 }}}....eq.2


from eq.1 and eq.2 we have

{{{ 200-x=3x-8 }}}

{{{ 200+8=3x+x }}}

{{{ 4x=208 }}}

{{{ x=208/4 }}}

{{{ x=52 }}}

go to eq.1 and substitute {{{x}}}

{{{ y=200-52 }}}

{{{ y=148 }}}