Question 1203169
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Benjamin went shopping with 15 more ten-dollar notes than two-dollar notes. 
He paid $270 for a jacket with some ten-dollar notes. 
In the end, the number of ten-dollar notes he had left was 1/3 
of the number of two-dollar notes he had left. 
How much money did he have at first?
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x of two-dollars notes and (x+15) of ten-dollars notes originally.


After paying $270 by ten-dollar notes, the number of remaining ten-dollar notes is ((x+15)-27) = x-12.


We are given  {{{(x-12)/x}}} = {{{1/3}}}.


Cross-multiply, simplify and find x

    3*(x-12) = x

    3x - 36 = x

    3x - x = 36

      2x   = 36

       x   =   36/2 = 18.


Thus originally, Benjamin went shopping with 18 two-dollars notes and 18+15 = 33 ten-dollar notes.

Hence, originally Benjamin had 10*33 + 2*18 = 366 dollars.    <U>ANSWER</U>
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Solved.