Question 1203169
Benjamin went shopping with 15 more ten-dollar notes than two-dollar 
notes.
<pre>
Let x = the number of two-dollar notes he had at first.
Let y = the number of ten-dollar notes he had at first.
</pre>
...15 more ten-dollar notes than two-dollar notes...
<pre>
So y = x+15
</pre>
He paid $270 for a jacket with some ten-dollar notes. 
<pre>
After buying the jacket he had y-27 ten-dollar notes.
</pre>
In the end, the number of ten-dollar notes he had left was 1/3 of the number
of two-dollar notes he had left. 
<pre>
So in the end he had x two-dollar notes because he didn't spend any.

   y-27 = (1/3)x

x+15-27 = (1/3)x

   x-12 = (1/3)x

  3x-36 = x

     2x = 36

      x = 18

y = x+15 = 18+15 = 33
</pre>
How much money did he have at first?
<pre>
He had 18 two-dollar notes and 33 ten-dollar notes at first.

Edwin</pre>