Question 1203076
To find the sample size required for a statistical hypothesis test with a certain power, we use the formula for the sample size in a two-sided hypothesis test:

n = [(Zα/2 + Zβ)^2 * (2 * σ^2)] / d^2

Where:

Zα/2 is the critical value of the Normal distribution at α/2 (for a two-sided test with a significance level of 0.05, the value of Zα/2 is 1.96)
Zβ is the critical value of the Normal distribution at β (for a test with a power of 0.80, β is 0.20, and the value of Zβ is 0.84)
σ is the standard deviation of the population (in your case, σ = 5.7)
d is the size of the effect you're looking for (in your case, the difference in scores, d = 2)
Plugging these values into the formula:

n = [(1.96 + 0.84)^2 * (2 * 5.7^2)] / 2^2
n = [(2.8)^2 * (2 * 32.49)] / 4
n = [7.84 * 64.98] / 4
n = 509.9152 / 4
n = 127.4788

Because you can't have a fraction of a student, you'd round up to the nearest whole number. Therefore, the researcher would need a sample size of 128 students to ensure that the two-sided test of hypothesis has 80% power to detect a difference in scores of 2 marks.