Question 115269
find the rectangular form of 4(cos(5/6 pi)+ i sin(5/6 pi))?
x = 4cos[(5/6)pi] = -3.464...
y = 4sin[(5/6)pi] = 2
rectangular form is -3.464+2i
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find the trigonometric form of sqrt3 - i?
r = sqrt((sqrt(3))^2 + 1^2)= 2
theta = tan^-1(-1/sqrt(3)) = 0.524 in radian measure
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trig form is 2cis(0.524...)
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Cheers,
Stan H.