Question 1203131
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100 candidates for 1st position;

 99 candidates for 2nd position  (the remaining students in the class);

 98 candidates for 3rd position  (the remaining students in the class).


In total, there are 100*99*98 = 970200 distinct ways.    <U>ANSWER</U>
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Solved in full, &nbsp;with comprehensive explanations.


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To see many other similar and different problems solved with complete explanations, &nbsp;look into the lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF =https://www.algebra.com/algebra/homework/Permutations/Special-type-permutations-problems.lesson>Special type permutations problems</A> 

in this site.


Learn the subject from there once and for all.


The standard mantra is the same for all such problems.


These problems relate to permutations, &nbsp;where the order in selected subsets &nbsp;(triples, &nbsp;in this case) &nbsp;<U>DOES &nbsp;MATTER</U>.