Question 115255
from a {{{24yd}}} length

{{{3}}} pieces , each {{{3 (1/2) yd}}} long,

{{{5}}} pieces, each {{{2 (1/4) yd}}} long are {{{removed}}}; therefore, you need to subtract the sum of removed pieces from a {{{24yd}}} length 

and {{{x}}} yards of material will {{{remain}}}

so:

{{{x = 24yd - (3*3(1/2)+ 5*2(1/4)yd)}}}


{{{x = 24yd - (3(7/2)+ 5(9/4)yd)}}}


{{{x = 24yd - (21/2+ 45/4)yd)}}}


{{{x = 24yd - (21*2/(2*2)+ 45/4)yd)}}}


{{{x = 24yd - (42/4 + 45/4)yd)}}}


{{{x = 24yd - ((42+45)/4)yd)}}}


{{{x = 24yd - (87/4)yd)}}}


{{{x = 24yd - (21(3/4)yd)}}}

{{{x = 2(1/4)yd}}}