Question 1203098
<pre>
{{{y = 3x - 1/(2x)}}}
Break up the fraction into the product of two fractions
{{{y = 3x - (1/2)(1/x)}}}
Write the x in the denominator as x<sup>-1</sup> in the numerator.
{{{y = 3x - expr(1/2)x^(-1)}}} 
Use the first principle of derivatives {{{d/dx}}}{{{(x^n)}}}{{{""=""}}}{{{n*x^(n-1)}}}
{{{dy/dx = "y'" = 3  - expr(1/2)(-1)x^(-2)}}} 
{{{dy/dx = "y'" = 3  + expr(1/2)x^(-2)}}} 

You can keep going by writing the negative exponent of x in
the numerator as a positive exponent of x in the denominator, 
then getting an LCD, etc.

Edwin</pre>