Question 1203090
<font color=black size=3>
{{{
drawing(400,400,-5,5,-5,5,
line(-3,3,-3,-3),
line(-3,-3,3,-3),
line(3,-3,-3,3),

line(-3,-3+0.8,-3+0.8,-3+0.8),
line(-3+0.8,-3+0.8,-3+0.8,-3),

circle(-3,3,0.04),
circle(-3,3,0.06),
circle(-3,3,0.08),
circle(-3,3,0.10),
circle(-3,3,0.12),
locate(-3-0.6,3+0.2,"C"),

circle(-3,-3,0.04),
circle(-3,-3,0.06),
circle(-3,-3,0.08),
circle(-3,-3,0.10),
circle(-3,-3,0.12),
locate(-3-0.6,-3+0.2,"D"),

circle(3,-3,0.04),
circle(3,-3,0.06),
circle(3,-3,0.08),
circle(3,-3,0.10),
circle(3,-3,0.12),
locate(3+0.2,-3-0.2,"E"),

locate(-3-1.8,0,matrix(1,2,"2.51","cm")),
locate(-1,-3-0.2,matrix(1,2,"2.46","cm")),

locate(-4.5,-4,matrix(1,2,"Diagram","not")),
locate(-4.5,-4.5,matrix(1,2,"to","scale"))

)
}}}


We have a right triangle, so we'll use the pythagorean theorem.
{{{(leg1)^2+(leg2)^2 = (hypotenuse)^2}}}


{{{(CD)^2 + (DE)^2 = (CE)^2}}}


{{{CE = sqrt((CD)^2 + (DE)^2)}}}
I'll let the student finish up.
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