Question 1203084


Show that if 

{{{abs(x+3)< 1/2}}} , then {{{abs(4x+13) < 3}}}



{{{abs(x+3) < 1/2}}}

{{{x+3 < 1/2}}}

{{{x< 1/2-3}}}

{{{x< -5/2}}}

or

{{{-(x+3) < 1/2}}}

{{{-x-3 < 1/2}}}

{{{-1/2-3 < x}}}

{{{-7/2<x}}}


solution:

{{{-7/2<x<-5/2}}}


choose an integer solution:

let say {{{x = -3}}} because {{{-7/2<-3<-5/2}}}

 then 

{{{abs(4(-3)+13) < 3}}}

{{{abs(-12+13) < 3}}}

{{{1< 3}}} => true