Question 115237
First convert 2x-3y =4 into slope-intercept form


*[invoke converting_linear_equations "standard_to_slope-intercept", 2, -3, 4, 2, 1]


Now let's find the line that is parallel to {{{y=(2/3)x-4/3}}} that goes through the point (4,-5)



*[invoke equation_parallel_or_perpendicular "parallel", "2/3", "-4/3", 4, -5]