Question 1202969
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(1)
{{{21-3(t-2)^2=9}}}<br>
The equation involves the square of an expression containing the variable, so probably the square root method is the most efficient.<br>
{{{12=3(t-2)^2}}}
{{{(t-2)^2=4}}}
{{{t-2=2}}} or {{{t-2=-2}}}
{{{t=4}}} or {{{t=0}}}<br>
ANSWERS: 0 and 4<br>
(2)
{{{x^2+12x-20=0}}}<br>
The equation is in the form needed for solving by factoring; but a quick look makes it appear that it does not factor.  We can confirm that by seeing that {{{b^2-4ac=144+80=224}}} is not a perfect square.  So use the quadratic formula.<br>
{{{x=(-12+-sqrt(224))/2}}}<br>
simplify as needed....<br>
(3)
{{{(x+3)(x-6)=-8}}}<br>
With "8" instead of 0 on the right, we can't solve this by the STANDARD factoring method.  So put the equation in standard form and try factoring, and if that doesn't look good use the quadratic formula.<br>
{{{x^2-3x-18=-8}}}
{{{x^2-3x-10=0}}}
{{{(x-5)(x+2)=0}}}
{{{x=5}}} or {{{x=-2}}}<br>
ANSWERS: -2 and 5<br>
While this one can't be solved by the standard factoring method, it CAN be solved by factoring using some logical reasoning.<br>
The product on the left is the product of two numbers whose difference is 9 and whose product is -8.  A little mental arithmetic shows that the two numbers can be 8 and -1, or 1 and -8.  Then<br>
If x+3 = 8 then x = 5; if x+3 = 1 then x = -2<br>
And again the two solutions are -2 and 5.<br>