Question 1202971
Since we know that it is a function of h(t), and expected that h(t) = 0 which means it has hit the ground; it can be said that we can obtain time (t), in such way {{{16t^2-96t-11=0}}}

By quadratic formula, {{{t = -0.11s}}} and {{{t = 6.11s}}}

Practically there's no such time existing at negatives so 6.11s should be the time to get into.

Now the domain can be dom h(t):(0, 6.11].