Question 1202926
<pre>
Change 'even' to 'odd' and you can do it.

Find two consecutive EVEN integers such that 50 more than the lesser
is five times the greater.

   G = L+2
L+50 = 5G

L+50 = 5(L+2)
L+50 = 5L+10
  40 = 4L
  10 = L
   G = L+2
   G = 10+2
   G = 12

10 and 12.

Or switch "greater" and "lesser" and you can do it.

Find two consecutive odd integers such that 50 more than the GREATER
is five times the LESSER.

     G = L+2
  G+50 = 5L

L+2+50 = 5L
  L+52 = 5L
    52 = 4L
    13 = L
     G = L+2
     G = 13+2
     G = 15.

13 and 15.

There is no solution as you have written it.  Maybe your teacher
was testing you to see if you'd know it has no solution.  Sometimes
the correct answer is "no solution".

Edwin</pre>