<PRE><B>Question 1202926</B>
.
Find two consecutive odd integers such that 50 more than the lesser 
is five times the greater.
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&lt;pre&gt;
Let the numbers be x and (x+2).

Then we can write this equation

    x + 50 = 5*(x+2).


Simplify and find x

    x + 50 = 5x + 10

    50 - 10 = 5x - x

       40   =   4x

        x   =   40/4 = 10.


It shows that the problem is posed INCORRECTLY.

Such odd integers as described in your post DO NOT EXIST,
and the problem describes a situation which never may happen.
&lt;/pre&gt;

Solved.


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