Question 1110806
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The response from the other tutor shows a good algebraic solution, starting with expressions for the bills A and B pay, then using those expressions to set up a proportion using the information that the ratio of the bills is 3:4.<br>
When the given information in a problem includes the ratio of two numbers, often an easier path to the solution is to start with that ratio.<br>
Let's see how the amount of work required with that method compares with the method used by the other tutor.<br>
Given the ratio 3:4...
let 3x = amount paid by A
let 4x = amount paid by B<br>
A paid the flat rate of Rs 300 for the first 50 calls plus Rs 1.5 for each of the remaining (90-50)=40 calls:<br>
3x = 300+1.5(40) = 360
x = 120<br>
The amount B paid was 4x = 480.<br>
If the number of calls above 50 B made is y, then<br>
300+1.5y = 480
1.5y = 180
y = 180/1.5 = 120<br>
The number of calls B made was 50+120 = 170.<br>
ANSWER: 170<br>
In this problem, the calculations required to reach the answer seem a bit easier than those required with the other method....<br>
Is this method better? Not necessarily.  The purpose of my response showing a very different path to the solution is not to show you a better method, but rather to show you that, when solving ANY problem (math problem, or any problem you encounter in your life!) you should always consider different possible ways of solving the problem.<br>