<PRE><B>Question 1079429</B>
Formula
V(t) = V_0e^kt,

1100 = 5000 *e^5k 

1100/5000 = e^5k

take the natural log of both sides 

ln(1100/5000) = ln(e^(5k))

ln(1100/5000) =5k

k = ln(1100/5000) / 5 = -.3028255465  (decay constant)


 Vt= V0 * e^(kt)
t=8 , V0 =5000, k we have found out

Plug the value of in  Vt = pV0* e^(kt) = 5000*e^(0-.3028255465*8)=443.45



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